9 sec square A-9 tan square A
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Answer:
9 IS THE ANSWER FOR THE GIVEN QUESTION
9 secant square A - 9 tan square A is equal to 9 (secant squared minus 10 square A) = 9×1=9
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Answer:
9 sec²A - 9 tan²A
= 9. 1/cos²A - 9 sin²A/cos²A
= 9/cos²A - 9 sin²A/cos²A
= 9 - 9 sin²A/cos²A
= 9(1 - sin²A)/cos²A
= 9 cos²A/cos²A [ 1 - sin²A = cos²A ]
= 9
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