Question

9 sec square A - 9 tan square A
answer is ​

Answer 1

Answer:

$9 { \sec(a) }^{2} - 9 { \tan(a) }^{2} \\ = 9 \\ = 9( { \sec(a) }^{2} - { \tan(a) }^{2} ) \\ = 9 \times 1 \\ = 9$

Answer 2

Answer:

sec^2A = tan^2A + 1

9sec^2 = 9tan^2A +9

therefore, 9sec^A - 9tan^2A = 9