Question

9 sec
square A - 9 tan square A is equal to​

Answer 1

Answer:

9................

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Answer 2

Answer:

⚠ _ Hello _ ⚠

Step-by-step explanation:

$9( { \sec(a) }^{2} - { \tan(a) }^{2} ) = 0 \\ we \: know \: that \: \\ { \sec(a) }^{2} - { \tan(a) }^{2} = 1 \\ = > 9 \times 1 \\ = > 9$

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