9 sec² A-9 tan² A =?
Answers
Answered by
16
Answer:
We have, 9sec2A−9tan2A
Let r=9sec2A−9tan2A
r=9(sec2A−tan2A)
We know that
sec2A−tan2A=1
Therefore,
r=9×1=9
Hence, this is the answer.
Step-by-step explanation:
hope it is helpful
Answered by
7
Step-by-step explanation:
9 sec^ A......this is one term
9 tan^A .......this is one term
9 is common in both terms
so we can write as
9(sec^A-tan^A)
since,sec^theta-tan^theta =1
so,9(1)
9
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