Question

9 sec² A-9 tan² A =?​

Answer 1

Answer:

We have,  9sec2A−9tan2A

Let  r=9sec2A−9tan2A

r=9(sec2A−tan2A)

We know that

sec2A−tan2A=1

Therefore,

r=9×1=9

Hence, this is the answer.

Step-by-step explanation:

hope it is helpful

Answer 2

Step-by-step explanation:

9 sec^ A......this is one term

9 tan^A .......this is one term

9 is common in both terms

so we can write as

9(sec^A-tan^A)

since,sec^theta-tan^theta =1

so,9(1)

9

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