Question

9 sec2 A − 9 tan2 A is equal to
A. 1

B. 9
C. 8
D. 0

Answer 1

Answer:

To find: 9 sec2 A – 9 tan2 A

Consider 9 sec2 A – 9 tan2 A = 9 (sec2 A – tan2 A)

∵ 1 + tan2 A = sec2 A

∴ 9 sec2 A – 9 tan2 A = 9 (sec2 A – tan2 A)

= 9 (1 + tan2 A – tan2 A) = 9

Answer 2

Answer:

take common 9 and we know the identity that is sec square theta - Tan square theta is 1 so 9 × 1 gives us 9 .