Math, asked by pk6705125, 1 month ago

9 Sec2 A - 9 tan2A
please solve this fast
it's urgent​

Answers

Answered by anudhaka879
2

Answer:

9 is the answer

Step-by-step explanation:

9sec²A-9tan²A

=(9/cos²A)-(9sin²A/cos²A) [ sec²A=1/cos²A]

[ tan²A=sin²A/cos²A]

=[ 9-9sin²A]/cos²A

=[9(1-sin²A)] / cos²A [sin²A +cos²A=1]

= [9 (cos²A)] /cos²A

= 9

I hope this will help you

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