Question

9 sec²A+3 cos²A 3 sin²A-9 tan²A​

Answer 1

Answer:

9sec

2

A−9tan

2

A,[1−sin

2

A=cos

2

A]

⇒

cos

2

A

9

−

cos

2

A

9sin

2

A

=

cos

2

A

9(1−sin

2

A)

=

cos

2

A

9cos

2

A

=9Ans.

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