Question

9 secant
$9 \sec( {a - 9 \tan(a) }^{2} )$
​

Answer 1

Answer:

We have, 9sec

2

A−9tan

2

A

Let r=9sec

2

A−9tan

2

A

r=9(sec

2

A−tan

2

A)

We know that

sec

2

A−tan

2

A=1

Therefore,

r=9×1=9

Hence, this is the answer.