Question

9. Show that in an isosceles triangle, an altitude from a vertex bisects the base.

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Answer 1

Step-by-step explanation:

et us take a triangle ABC and draw an altitude CD

being an isosceles triangle

in ΔACD and ΔCDB

CD=CD (common )

CA=CB ( equal opposite sides)

∠ A=∠ B ( angle opposite to opposite sides are also equal )

therefore : ΔACD and ΔCDB are congruent by ASA rule

so , AD=DB by CPCT

So, its true

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