Question

9. Show that (tan 0 + 2) (2 tan 0 + 1) = 5 tan 0 + 2 sec 0.​

Answer 1

Answer:

tan(@+2)×(2tan@+1)

= 2tan²@+5tan@+2

= 2(tan²@+1)+5tan@

= 2sec²@+5tan@