Physics, asked by tneeta57, 7 months ago

9. Shreya is moving with velocity (in km/hr)
6^i-4^j and Divya
is moving with velocity (in km/hr) -2^1 + 5^j
What is the
velocity (in km/hr) of Divya relative to that
of Shreya?
4^i+ 9^j
-8^i + 9^j
4^i +^ j
8^i +^j​

Answers

Answered by TanmayKiranUrunkar
2

Answer:

let V1=6i-4j

V2= -2i+5j

velocity (in km/hr) of Divya relative to that

of Shreya is V2-V1= -2i+5j-6i+4j= -8i+9j

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