Question

9. Sides of a triangle are of lengths 28 cm, 30 cm and 26 cm. Area of the triangle is:​

Answer 1

Answer:

Hi friends

Step-by-step explanation:

a= 26cm

b= 28cm

c=30cm

s= a+b+c/2 =42cm

According to Heron's formula, Area of a ? is equal to root of s(s-a)(s-b)(s-c).

Therefore, area of ?= root of 42(42-26)(42-28)(42-30)

= root of 42*16*14*12

= root of 112896

= 336 cm square Answer

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Answer 2

$\large{ \bold{ \color{blue}{ \underline{ \color{blue}{Question : - }}}}}$

Sides of a triangle are of lengths 28 cm, 30 cm and 26 cm. Area of the triangle is:

$\large{ \bold{ \color{blue}{ \underline{ \color{blue}{Answer : - }}}}}$

Let,

a = 28 cm

b = 30 cm

C = 26 cm

Semi perimeter -

$\frac{a + b + c}{2}$

$\frac{28 + 30 + 26}{2} \\ \\ 42 \: cm$

Using Heron's Formula -

$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ \sqrt{42(42 - 26)(42 - 28)(42 - 36)} \\ \\ \sqrt{42 \times 16 \times 14 \times 12} \\ \\ \sqrt{112896} \\ \\ 336 \: cm {}^{2}$

$\large \bold{ \color{blue}{@ISHU }}$