9. Simplify the following by grouping the numbers in as many ways as you can. 29 +38+25
871+129+371
7564+2122+436
Answers
Step-by-step explanation:
m eet.g oog le.c om/dct-rpww-tqk
Answer:
given rational numbers into terminating and non-terminating recurring type.
(i)
13
5
(ii)
2
11
(iii)
29
16
(iv)
17
125
(v)
11
6
ANSWER:
(i)
13
5
Since, 5=20×51
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
13
5
will be terminating type.
(ii)
2
11
Since, 11=20×50×111
⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
2
11
will be non-terminating recurring type.
(iii)
29
16
Since, 16=24×50
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
29
16
will be terminating type.
(iv)
17
125
Since, 125=20×53
⇒ The denominator is in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
17
125
will be terminating type.
(v)
11
6
Since, 6=21×50×31
⇒ The denominator is not in the form of 2m×5n, where m and n are non-negative integers.
So, the decimal form of
11
6
will be non-terminating recurring type.
