Question

9
sin^2(60°) + cos² (60°) + tan 45º + tan (135°) – cot 45°​

Answer 1

Answer:

sin^2(60)°+cos^2(60)°+tan 45°+tan 135°-cot 45°

=1+1+tan(90+45)°-1. [we know sin^2¢+cos^2¢=1]

=1-cot 45°

=1-1

=0

Answer 2

sin^2(60) + cos^(60)+ Tan45 + tan(135)- cot 45

1+1+(-1)- 1 ( tan (135) =-1 )

2+(-2)

0 .

I hope this helps you