Question

9. sin [2cos invers(3/5),
​

Answer 1

Answer:

sin106

Explanation:

sin[2cos^-1(3/5)]

=sin[2×53°]

=sin106

Answer 2

$cosx^{-1} 3/5=57x^{o}$

sin2θ=2sinθ.cosθ

sin(2x57)=2sin57.cos57

               =2x3/5x4/5

               =24/25

: )