9 sinA + 40 cos A = 41 find the value of sinA, cosA with full solution
Answers
Answered by
1
9sinA+40cosA=41
9sinA/cosA+40cosA=41
9sinA+40=41
9sinA=41-40=1
sinA =1/9
putting value of sinA
cosA=1
sin A= 1/9
.. is it correct?
9sinA/cosA+40cosA=41
9sinA+40=41
9sinA=41-40=1
sinA =1/9
putting value of sinA
cosA=1
sin A= 1/9
.. is it correct?
jitendrakoch123:
May be wrong answer
may bee.. I also
Similar questions