Question

9. Solve : 3(x+2) - 2(x-1)= 11 by trial and error method.​

Answer 1

Step-by-step explanation:

trial and error method :

putting x = 1

3(1+2) - 2(1-1) = 11

3(3) - 2(0) = 11

9 - 0 = 11

LHS ≠ RHS

putting x = 2

3(2+2) - 2(2-1) = 11

3(4) - 2(1) = 11

12 - 2 = 11

10 - 11

LHS ≠ RHS

putting x = 3

3(3+2) - 2(3-1) = 11

3(5) - 2(2) = 11

15 - 4 = 11

11 = 11

LHS = RHS

hence, x = 3 is the correct answer

Answer 2

Answer:

Let the value of x be 1

3(x+2) - 2(x-1)= 11

⇒ 3(1 + 2) - 2(1 - 1) = 11

⇒ 3(3) - 2(0) = 11

⇒ 9 - 0 = 11

⇒ 9 ≠ 11

Over here, the L.H.S is not equal to the R.H.S, so, x is not 1

Let the value of x be 2

3(x+2) - 2(x-1)= 11

⇒ 3(2 + 2) - 2(2 - 1) = 11

⇒3(4) - 2(1) = 11

⇒ 12 - 2 = 11

⇒ 10 ≠ 11

Over here, the L.H.S is not equal to the R.H.S, so, x is not 2

Let the values of x be 3

3(x+2) - 2(x-1)= 11

⇒ 3(3 + 2) - 2(3 - 1) = 11

⇒ 3(5) - 2(2) = 11

⇒ 15 - 4 = 11

⇒ 11 = 11

Over here, the L.H.S is equal to the R.H.S, so, x is 3

∴ Hence, we have proved that x is equal to 3 by trail and error method.

Thnx and have a nice day!

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