Question

9. Solve the following equations:
a) 2x -12 = 18
b) 2(y - 4) = 10​

Answer 1

a)2x-12=18

2x=18-12

2x=6

x=3.

b) 2y-8=10.

2y=10+8

2y=18

y=9.

Answer 2

$\huge \bold \pink {solution}$

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$\small \bold \red{ \: a) \: 2x -12 = 18}$

1stly We have to add 12 to both sides of equation

2x - 12 = 18

→2x-12 +12 =18 +12

2ndly then we have to add the numbers and we get

↓

→2x =30

3rdly then we have to divide both sides of the equation by same term

→2x =30

${→ \frac{2x}{2} = \frac{30}{2} }$

Lastly then we have to cancel terms that are in both the numerator and denominator

↓

then we have to divide the numbers and we get

↓

x=15

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$\small \bold \red{b) \: 2(y - 4) = 10}$

1stly we have to distribute it

2(y-4)=10

→2y-8=10

Secondly we have to add 8 to both sides of the question

2y- 8 =10

→2y-8 + 8 =10+8

thirdly we have to add the numbers

→2y=18

Fourthly we have to divide both sides of the equation by the same term

2y=18

$→ \frac{2y}{2} = \frac{18}{2}$

lastly we have to cancel terms that are in both numerator and denominator and divide the numbers

↓

y=19