Question

9. Subtract the sum of -11/5 and -2/3 from the sum of 3/5 and 7/3
plz explain full with taking lcm​

Answer 1

Answer:

Given:-

Subtract the sum of $- \ \dfrac{11}{5}$ and $- \ \dfrac{2}{3}$ from the sum of $\dfrac{3}{5}$ and $\dfrac{7}{3}$.

To Find:-

Subtraction of the given sum.

Note:-

●》Here, we will first add the given numbers and then we will subtract second sum to first sum.

●》Positive × Negative = Negative, Negative × Negative = Positive; In this methods at last, greater sign will be there.

Solution:-

$\huge\red{Sum \ \ of \ \ - \ \dfrac{11}{5}, - \ \dfrac{2}{3} = ?}$

☆ So~

▪︎$- \ \dfrac{11}{5} + - \ \dfrac{2}{3}$

☆ L.C.M = 15~

▪︎$- \ \dfrac{11}{5} × \dfrac{3}{3} + - \ \dfrac{2}{3} × \dfrac{5}{5}$

▪︎$- \ \dfrac{33}{15} + - \ \dfrac{10}{15}$

☆ According to note second point~

▪︎$- \ \dfrac{33}{15} - \dfrac{10}{15}$

▪︎$- \ \dfrac{43}{15}$

$\huge\pink{Sum \ \ of \ \ - \ \dfrac{11}{5}, - \ \dfrac{2}{3} = - \ \dfrac{43}{15}}$

__________________________________________

$\huge\red{Sum \ \ of \ \ \dfrac{3}{5}, \dfrac{7}{3} = ?}$

☆ So~

▪︎$\dfrac{3}{5} + \dfrac{7}{3}$

☆ L.C.M = 15~

▪︎$\dfrac{3}{5} × \dfrac{3}{3} + \dfrac{7}{3} × \dfrac{5}{5}$

▪︎$\dfrac{9}{15} + \dfrac{35}{15}$

▪︎$\dfrac{44}{15}$

$\huge\pink{Sum \ \ of \ \ \dfrac{3}{5}, \dfrac{7}{3} = \dfrac{44}{15}}$

__________________________________________

[ Now, we will subtract the terms ]

$\huge\red{Subtraction \ \ of \ \ - \ \dfrac{43}{15} \ \ from \ \ \dfrac{44}{15} = ?}$

☆ According to note first point~

▪︎$\dfrac{44}{15} - - \ \dfrac{43}{15}$

☆ According to note second point~

▪︎$\dfrac{44}{15} + \dfrac{43}{15}$

☆ After doing calculations~

▪︎$\dfrac{87}{15}$

☆ Mixed fraction~

▪︎$5 \ \dfrac{12}{15}$

$\huge\green{Subtraction \ \ of \ \ - \ \dfrac{43}{15} \ \ from \ \ \dfrac{44}{15} = \dfrac{87}{15} \ \ or \ \ 5 \ \dfrac{12}{15}}$

Answer:-

Hence, the Subtraction of the given sum = $\dfrac{87}{15} \ \ or \ \ 5 \ \dfrac{12}{15}$

:)