Chemistry, asked by nooralzahraa2014, 19 days ago

9-Suggest the pressure and temperature at which 1.0 mol of (a) H2S, (b) CO2, (c) Ar will be in states that correspond to 1.0 mol N2 at 1.0 atm and 25°C.​

Answers

Answered by johnsinajothi24
2

          To compare the corresponding states among different elements, the reduced pressure, temperature, of the elements must be same. The reduced temperature and pressure are defined as

               Pr = Pm/Pc,  Tr = Tm/Tc

Where,

Pr = Reduced pressure, Pc = Critical pressure

Tc = Critical temperature, Tr = Reduced temperature

Pm = Actual pressure, Tm = Actual temperature

We know,

The Critical pressure of Nitrogen = 33.55 atm

The Critical temperature of Nitrogen = 126.2K

The actual temperature of Nitrogen = 25 degree celcius = 298.12K

The actual pressure of Nitrogen = 1atm

a)Calculating the pressure and Temperature of Hydrogen sulfide

We know,

The Critical temperature of Hydrogen sulfide = 373.5K

The Critical pressure of Hydrogen sulfide = 89atm

Equating the reduced pressures and temperatures both the gases we have,

Pr for Nitrogen = Pr for Hydrogen sulfide

                 Pm/Pc = pm/Pc

                1/33.55 = Pm/89

                 Pm = 1×89/33.55

                        =2.652atm

Tr for Nitrogen = Tr for Hydrogen sulfide

              Tm/Tc = Tm/Tc

            298.15/126.2 = Tm/373.5

              Tm = 298.15×373.5/126.2

                    = 882.4K

b)Calculating the pressure and temperature for carbon dioxide

We know,

The Critical, temperature for Carbon dioxide = 304.25K

The Critical pressure for Carbon dioxide = 72.9atm

Equating the reduced pressure and temperature of both the gases we have,

Pr for Nitrogen = Pr for Carbon dioxide

           Pm/Pc = Pm/Pc

           1/33.55 = Pm/72.9

                Pm = 1×72.9/33.55

                      = 2.173atm

Tr for Nitrogen = Tr for Carbon dioxide

              Tm/Tc = Tm/Tc

              298.15/126.2 = Tm/304.25

                       Tm = 298.15×304.25/126.2

                             = 718.8K

c)Calculating the pressure and temperature of Argon

We know,

The Critical temperature for Argon = 151.15K

The Critical pressure for Argon = 48.1atm

Equating the reduced pressures and temperatures of both the gases we have,

Pr for Nitrogen = Pr for Argon

           Pm/Pc = Pm/Pc

           1/33.55 = Pm/48.1

                 Pm = 1×48.1/33.55

                       = 1.433atm

Tr for Nitrogen = Tr for Argon

              Tm/Tc = Tm/Tc

              298.15/126.2 = Tm/151.15

                        Tm = 298.15×151.15/126.2

                             = 357.1K

a)Pressure = 2.652atm, Temperature = 882.4K

 b)Pressure = 2.173atm, Temperature = 718.8K

 c)Pressure = 1.433atm, Temperature = 357.1K

Answered by mindfulmaisel
1

a)Pressure = 2.652atm, Temp = 882.4K

b)Pressure = 2.173atm, Temp = 718.8K

c)Pressure = 1.433atm, Temp = 357.1K

Explanation:

a)pressure and Temperature of Hydrogen sulfide;

Pr for Nitrogen = Pr for Hydrogen sulfide

                Pm/Pc = pm/Pc

               1/33.55 = Pm/89

                Pm = 1×89/33.55

                       =2.652atm

Tr for Nitrogen = Tr for Hydrogen sulfide

             Tm/Tc = Tm/Tc

           298.15/126.2 = Tm/373.5

             Tm = 298.15×373.5/126.2

                   = 882.4K

b)pressure and temperature for carbon dioxide:

Pr for Nitrogen = Pr for Carbon dioxide

          Pm/Pc = Pm/Pc

          1/33.55 = Pm/72.9

               Pm = 1×72.9/33.55

                     = 2.173atm

Tr for Nitrogen = Tr for Carbon dioxide

             Tm/Tc = Tm/Tc

             298.15/126.2 = Tm/304.25

               Tm = 298.15×304.25/126.2

                           = 718.8K

c)pressure and temperature of Argon:

Pressure for Nitrogen = Pressure for Argon

          Pm/Pc = Pm/Pc

          1/33.55 = Pm/48.1

                Pm = 1×48.1/33.55

                      = 1.433atm

Tr for Nitrogen = Tr for Argon

             Tm/Tc = Tm/Tc

             298.15/126.2 = Tm/151.15

               Tm = 298.15×151.15/126.2

                            = 357.1K

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