Question

9. Sunny purchases 6 oranges for 25 rupees and sells 5 oranges for 25 rupees,
then find the profit percentage?​

Answer 1

Sunny purchases 6 oranges for 25 rupees and sells 5 oranges for 25 rupees,

then find the profit percentage?

Cost price of 6 oranges = 25 Rs.

Cost price of 1 orange = 25/6 = 4 1/6 Rs.

Selling price of 5 oranges = 25 Rs

Selling price of 1 orange = 5 Rs.

Since, The question doesn't tell about what happened to the sixth orange, We would calculate profit/loss on each orange considering the last orange is also sold at same cost.

So CP ( 4 1/6) < SP ( 5)

There's a profit

profit = 5 - 4 1/6 = 5/6

Profit %

= 5/6 ÷ 25/6 * 100

= 5/6 * 6/25 * 100

= 100/5

= 20%

Therefore, there is a 20% profit on each orange.

Therefore, there is a 20% profit on each orange.

Answer 2

Answer=20%

Note[•°•]

CP=>Cost price

SP=>Selling price

$CP \: of \: oranges (6 = 25 Rs)$

$CP \: of \: orange \: ( 1 = \frac{25}{6} = \frac{41}{6} Rs)$

$SP \: of oranges \: (5 oranges = 25 Rs) \\ </p><p>SP \: of \: orange (1= 5 Rs)</p><p>$

Now let us take the last orange is sold at the same pice

Hence,

$CP \frac{41}{6} < SP ....(( 5))</p><p>$

$profit = 5 \: \frac{ - 41}{6} = \frac{5}{6} </p><p>$

$= ( \frac{5}{6} ÷ \frac{25}{6} = 100)</p><p>$

$= (\frac{5}{6} .. \frac{6}{25} = 100)</p><p>$

$= \frac{100}{5}$

= 20%

Hence profit of every orange =20%

Error and plagiarism free answer✔️