Question

9. Suppose two gases in a container have a total pressure of 1.20 atm. What is the pressure of gas B if the partial pressure of gas A is 0.75 atm?

Answer 1

Hi,,

According to Dalton's law

Total pressure for gas mixture is equal the sum of partial pressure of each gas

P(t)= P(a)+P(b)

1.2 = 0.75 + P(b)

P(b) = 1.2 - 0.75= 0.45 atm

Hope the answer is helpful

Answer 2

The partial pressure of gas B is 0.45 atm

Explanation:

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the partial pressure of gas B, we use the law given by Dalton, which is:

$P_T=p_{A}+p_{B}$

We are given:

Total pressure of the container, $P_T$ = 1.20 atm

Vapor pressure of gas A, $p_{A}$ = 0.75 atm

Putting values in above equation, we get:

$1.20=0.75+p_{B}\\\\p_{B}=1.20-0.75=0.45atm$

Learn more about Dalton's Law:

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