Question

9.
tan | x |=| tan x| if.....​

Answer 1

Answer:

tanx+secx∣=∣tanx∣−∣secx∣

Then tanx.secx≤0 and ∣tanx∣≥∣secx∣

Now,∣tanx∣≥∣secx∣

⇒tan

2

x≥sec

2

x

⇒tan

2

x≥1+tan

2

x⇒0≥1 This is not possible.