Question

9
$9x^-Kx+16=0$
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Answer 1

Answer:

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Answer 2

For the equation to have equal roots ,

The value of determinant should be zero.

i.e. D=b²-4ac=0———(1)

Where in this case,

b=8k

a=9 , and

c=16

Substituting the above values in (1)

=>64k²-4*9*16=0

=>64k²-576=0

=>64k²=576

=>k²=576/64

=>k²=9

=>k=+3 or -3

Hence , for the equation nto have equal roots the value of k is either +3 or -3

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