Question

9. The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3:2. Find their present ages please answer step wise and type it if you follow the commands i will mark you as brainliest

Answer 1

Answer:

Present age of A = 20

Present age of B = 15

Step-by-step explanation:

Let age of B = x

Let age of A = x + 5

5 years ago,

Age of B = x - 5

Age of A = x + 5 - 5

Ratio of their Ages = 3:2

3/2 = x + 5 - 5/ x - 5

Cross Multiplication :

⇒ 3(x - 5) = 2(x + 5 - 5)

⇒ 3x - 15 = 2x + 10-10

⇒ 3x-2x = 15

⇒ x = 15

Present age of B = 15

Present age of A = x + 5

⇒ x + 5 = 15 + 5 = 20

Answer 2

Step-by-step explanation:

Let the age of A be 'x' and

the age of B be 'y'.

A is five years more than that of

B⇒x=y+5-----(1)

5 years ago,

the ratio of their ages is 3:2

⇒(x-5)/(y-5)=3/2

⇒2x-10=3y-15

⇒2x-3y=-5------(2)

Substituting (1) in (2),

⇒2(y+5)-3y=-5

⇒2y+10-3y=-5

⇒-y=-15

⇒y=15.

From (1),x=y+5

⇒x=15+5

⇒x=20.

∴A is 20 years old and B is 15 years old.