Question

9. The base of a triangular field is three times its altitude. If the cost of levelling the field at 30.50 pa
sq. metre is 7350, find its base and height.
thich diagonals AC and BD measure 52 m and 36
​

Answer 1

Answer:

.

Step-by-step explanation:

We know the area of a triangle =$\frac{1}{2} </p><p> (base) x (altitude)$

=> area, A =$\frac{1}{2}[tex] </p><p></p><p></p><p>Price of levelling the field of area A = A x 30.50</p><p>Given : 30.50 A = 7350</p><p> => A = 240.98 sq.metre</p><p></p><p>Therefore, [tex]\frac{3}{2} a^{2}$

=240.98

=> a = 12.67 metre

Hence, altitude length = 12.67 metre , and base length = 38.01 metre