Question

9. The binding energy of electron in a
metal is 300 kJ mol-1. The threshold
frequency is
(a) 4.52 · 1015 s-1
(b) 5.72 · 1016 s-1
(c) 7.52 · 1014 s-1
(d) 9.25 · 1016
S-1​

Answer 1

Pls mark me as brainliest

Ur answer is option
C

Answer 2

Answer:

the threshold frequency is 7.4 X 10⁵ GHz

Explanation:

Given

E = 300 KJ/mol ⇒ 300000 J/mol

threshold frequency (ν) = ??

Solution

as we know that

E = hν

ν = E / h

where h = 6.6 X 10⁻³⁴ Js

ν = 300000 / 6.6 X 10⁻³⁴

ν = 0.45 X 10³⁹ Hz

for per atom

ν = 0.45 X 10³⁹ / 6.022 X 10²³

ν = 0.074 X 10¹⁶

ν = 7.4 X 10¹⁴ Hz

ν = 7.4 X 10⁵ GHz

option (c) is the correct answer

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