Question

9. The C.S.A of a right circular cylinder of height 14 cm is 88 cm find the diameter of the base of the cylinder​

Answer 1

$\huge \sf {\blue{\underline {\pink{\underline {A᭄ɴsᴡᴇʀ࿐ \ :- }}}}}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = \cancel {2} \times \pi \times \dfrac{x}{\cancel {2}}\times 14}\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = \pi \times x\times 14}\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = \dfrac{22}{\cancel {7}} \times x\times \cancel {14}}\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = 22 \times x \times 2 }\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = 44 \times x }\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ \dfrac{\cancel {88}}{\cancel {44}} = 44 \times x }\\\\\end{gathered}$

$\begin{gathered}\underline {\boxed{\red{ \mathrm { x = 2\: cm}}}}\:\bf{\bigstar}\\\end{gathered}$

Therefore,

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$\begin{gathered}\underline {\therefore\:{ \mathrm { Hence,\:Diameter \:of\:Cylinder \:is\:\bf{2\: cm}}}}\\\end{gathered}$

∴ Hence,DiameterofCylinderis2cm

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Answer 2

Answer:

$\huge \sf {\blue{\underline {\pink{\underline {A᭄ɴsᴡᴇʀ࿐ \ :- }}}}}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = \cancel {2} \times \pi \times \dfrac{x}{\cancel {2}}\times 14}\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = \pi \times x\times 14}\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = \dfrac{22}{\cancel {7}} \times x\times \cancel {14}}\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = 22 \times x \times 2 }\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ 88cm^{2} = 44 \times x }\\\\\end{gathered}$

$\begin{gathered}:\implies \sf{ \dfrac{\cancel {88}}{\cancel {44}} = 44 \times x }\\\\\end{gathered}$

$\begin{gathered}\underline {\boxed{\red{ \mathrm { x = 2\: cm}}}}\:\bf{\bigstar}\\\end{gathered}$

Therefore,

⠀⠀⠀⠀⠀

$\begin{gathered}\underline {\therefore\:{ \mathrm { Hence,\:Diameter \:of\:Cylinder \:is\:\bf{2\: cm}}}}\\\end{gathered}$

∴ Hence,Diameter of Cylinder is 2cm

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