Question

9) The conjugate of the complex 2 Jun
number (2+5i)/(4-3i) is *
​

Answer 1

Answer:

Conjugate of

4−3i

2+5i

is

Multiply & divide 4+3i

(4+3i)(4−3i)

(2+5i)(4+3i)

=

16+9

8+6i+20i−1

⇒

16+9

26i−7

∴ Conjugate is

25

−7−26i

∴ Conjugate of a+ib=a−ib.

solution