Question

9. The diagonal of a quadrilateral shaped field is 25 m and the perpendiculars dropped on
the remaining opposite vertices are 18 m and 12 m. Find the area of the field.​

Answer 1

Given:

The diagonal of a quadrilateral shaped field is 25 m and the perpendiculars dropped on the remaining opposite vertices are 18 m and 12 m.

To find:

The area of the field

Solution:

We know the formula as,

$\boxed{\bold{Area \:of\:a\:quadrilateral = \frac{1}{2}\times [Diagonal \:length] \times [sum\:of\:perpendiculars] }}$

The length of the diagonal of the quadrilateral shaped field = 25 m

The perpendiculars drawn from the two opposite vertices are 18 m & 12 m

Now, by substituting the values in the above formula, we get

The area of the quadrilateral shaped field is,

= $\frac{1}{2}\times 25 \times [18 + 12]$

= $\frac{1}{2}\times 25 \times 30$

= $\bold{375\:m^2}$

Thus, the area of the field is → 375 m².

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Answer 2

Answer:

wei wei

Step-by-step explanation:

its not a parallelogram so dont use that formula

i learnt it the hard way