Question

9) The diagonals of a rhombus are 7.5cm and 12cm.Find
Its area?​

Answer 1

Given : The diagonals of a rhombus are 7.5cm and 12cm.

Need To Find : Area of Rhombus.

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❍ Let's Consider $d_1\:\& \:\:d_{2}$ be two diagonals of Rhombus.

$\dag\frak{\underline { Area \:of\:Rhombus \::}}$

$\qquad \bf{\star\underline {Area_{(Rhombus)} = \dfrac{1}{2}\times d_{1}\times d_{2} \:sq.units}}$

Where ,

• $d_{1}\:\& \:\:d_{2}$ are two diagonals of Rhombus

⠀⠀⠀⠀⠀⠀$\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad:\implies \sf {Area_{(Rhombus)}=\dfrac{1}{2}\times 7.5 \times 12 }$

$\qquad:\implies \sf {Area_{(Rhombus)}=\dfrac{1}{\cancel {2}}\times 7.5 \times \cancel{12} }$

$\qquad:\implies \sf {Area_{(Rhombus)}= 7.5 \times 6 }$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Area _{(Rhombus)} = 45\: cm^{2}}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Area \:of\:Rhombus \:is\:\bf{45\: cm^2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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