Question

9. The diagram shows the straight line, which passes through the points (0,3)
and (4,11) find the equation in form of y=mx+c​

Answer 1

SOLUTION

GIVEN

The line is passing through the points (0,3) and (4,11)

TO DETERMINE

The equation of the line in the form y = mx + c

EVALUATION

Here it is given that the is passing through the points (0,3) and (4,11)

Hence the required equation of the line is

$\displaystyle \sf \: \frac{y - 3}{x - 0} = \frac{11 - 3}{4 - 0}$

$\displaystyle \sf \implies \frac{y - 3}{x } = \frac{8}{4}$

$\displaystyle \sf \implies \frac{y - 3}{x } =2$

$\displaystyle \sf \implies y - 3 = 2x$

$\displaystyle \sf \implies y = 2x + 3$

Which is of the form y = mx + c

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Answer 2

Answer:

Step-by-step explanation: