9. The digits of a 2-digit number differ by 5. If the digits are interchanged and the resulting number is added to the original number, we get 99. Find the original number.
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HEYA@USER
HERE IS THE ANSWER
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Let us assume, the x and y are the two digits of a two-digit number.
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x - y = 5 -------------1
Also given:
10x + y + 10y + x = 99
11x + 11y = 99
x + y = 9 --------------2
Adding equation 1 and equation 2
2x = 14
x = 7
Therefore, y = x - 5 = 7 - 5 = 2
Therefore, the two-digit number = 10x + y = 10*7 + 2 = 72
HOPE IT HELPS YOU
HERE IS THE ANSWER
_____________________
↔↔↔↔↔↔↔↔↔↔
Let us assume, the x and y are the two digits of a two-digit number.
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x - y = 5 -------------1
Also given:
10x + y + 10y + x = 99
11x + 11y = 99
x + y = 9 --------------2
Adding equation 1 and equation 2
2x = 14
x = 7
Therefore, y = x - 5 = 7 - 5 = 2
Therefore, the two-digit number = 10x + y = 10*7 + 2 = 72
HOPE IT HELPS YOU
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