Question

9. The dimensions of a field are 15 m x 12 m. A pit 7-5 mx 6 m * 1-5 m is dug in one corner
of the field and the earth removed from it, is evenly spread over the remaining area of the
field. Calculate, by how much the level of the field is raised​

Answer 1

Answer:

Length (L)=15 m,

Breadth (B)=12 m,

Dimensions of the Pit:

length (l)= 7.5 m,

width (b)=6 m,

depth (h)=1.5 m,

According to the problem given,

If the pit is dug at one corner of the field and earth removed is evenly spread over the remaining area of the field.

Now,

Area of the remaining field

= Area of the field - base area of the pit

= LB - lb

= 15 × 12 - 7.5 × 6

= 180 m² - 45 m²

= 135 m²