Question

9. The electrode potential of 4 metallic elements(A,B,C&D) are +0.80,-0.76,
+0.15, +0.34 V. Calculate the EMF of cell in each case with A as anode and
other as cathode.​

Answer 1

Explanation:

Standard reduction potential of Ag

+

/Ag=0.80V.

Standard reduction potential of Cu

2+

/Cu is less than Ag

+

/Ag.

∴Ag

+

/Ag will get reduced at cathode.

Cu

2+

/Cu will get oxidized at anode.

∴E

cell

∘

=E

cathode

∘

−E

anode

∘

E

cell

∘

=0.80−0.34=0.46V.