Question

9.
The father's age is 6 times that of his son. If the difference in their ages is 25 years, find their ages.​

Answer 1

Answer:

sons age will equal the father's present age. Find their present ages?

IIT Roorkee data science & machine learning program.

André Abadie

Answered August 16, 2018

There are two things we already know.

The father is 6 times as old as his son. In an equation, this would be written as: f=6s (Let “f” represent the fathers age and let “s” represent the son’s age).

The son will be as old as the father in 35 years. The equation for this is s+35=f

In the end, we are left with two equations:

f=6s

f=s+35

Now, we can substitute each equation into the other to find the value for each of their ages.

First, we’ll find the value for s.

s+35=6s

5s=35

s=35/5

s=7

Then, we’ll substitute the value of s into one of our two equations.

f=6s

f=6(7)

f=42

It doesn’t matter which equation we use; we’ll end up with the same answer.

Our second equation also gives us the value of 42:

f=s+35

f=7+35

f=42

Therefore, the son is 7 years of age, and the father is 42.

Answer 2

Answer:

Assume father’s present age = X1; Son’s present age = X2 ==> X1 = 6 X2.

X2 + 35 = X1 => X2 + 35 = 6 X2 => 35 = 5 X2 or X2 = 35/5 = 7; X2= 7*6 = 42.

Thus: Father’s present age = 42 ; Son’s present age = 7, because after 35 years,

Son’s age = 42 which is equal to Father;s present age, and 42 = 7 * 6.