Question

9. The Fig. 14.36 shows the cross section of a pipe.
Calculate:
(a) the area of cross section.
(b) the volume of a 63 cm long pipe.
Please send correct answer.... ​

Answer 1

Answer:

||☆》Question -:

The Fig. 14.36 shows the cross section of a pipe.

Calculate:

(a) The area of cross section.

(b) The volume of a 63 cm long pipe.

||☆》Given -:

From the figure,

We get to know

• The radius of the bigger circle = 5 cm.
• The radius of the smaller circle = 4 cm.

||☆》To Find -:

(a) The area of cross section.

(b) The volume of a 63 cm long pipe.

||☆》Solution -:

(a) The area of cross section.

$\implies$ Area of bigger circle = $\pi R^2$

$\rightarrow \pi 5^2$

$\rightarrow 25 \pi \ cm^2$

$\implies$ Area of smaller circle = $\pi r^2$

$\rightarrow \pi 4^2$

$\rightarrow 16 \pi \ cm^2$

$\therefore$ Area of cross section = Area of bigger circle - Area of smaller circle

$\rightarrow 25 \pi - 16 \pi$

$\longrightarrow 9 \pi \ cm^2$

(b) The volume of a 63 cm long pipe.

We know that,

Volume of a cylindrical pipe is = Length of pipe × area of crosssection or $\pi r^2 h$

So,

$\ Volume \ of \ a \ 63 \ cm \ long \ pipe \\ considering \ its \ thickness = 63 × 25 \pi$

$\implies 1575 \pi \ cm^3$

$\ Volume \ of \ a \ 63 \ cm \ long \ pipe \ without \\ considering \ its \ thickness = 63 × 16 \pi$

$\implies 1008 \pi \ cm^3$

||☆》Answer -:

(a) The area of cross section = $9 \pi \ cm^2.$

(b) The volume of a 63 cm long pipe

$\implies 1575 \pi \ cm^3$ [ Considering its thickness ].

$\implies 1008 \pi \ cm^3$ [ Without considering its thickness ].

________________________________

________________________________

Answer 2

Answer:

||☆》answer for this question

HoPe iT hElPs u