Question

9.
The ionic radii of S-2 and Te-2 are 1.84 and
2.21 A respectively. The ionic radii of Se-2 is
(1) 1.83 A
(2) 2.22 A
(3) 4.5 Å
(4) 2.02 A​

Answer 1

Answer:

The radius increases while moving down the group.

In a group, S Se Te is the form of increasing radius.

Thus the radius of Se should be in between the radius of S and Te.

Thus, the ionic radius of Se 2 = 2.02

So option D is correct.

Answer 2

Solution: Ionic Radii of Se^2- = (1.84 + 2.21)/2 = 2.02 A

Explanation:  Ionic radius of Se^2− is expected to be in between the ionic radii of S^2−  and Te^2−