Math, asked by doll1548, 5 months ago

9. The length and the breadth of a rectangular park are in the ratio 8 : 5. A path 1.5 m wide, running all
around the outside of the park has an area of 594 m². Find the dimensions of the park.​

Answers

Answered by TheRose06
3

\huge\underline{\bf \orange{AnSweR :}}

  • [Hint. Let the length and the breadth of the plot be 8x and 5x metres respectively. Then,
  • Area of the path = [(8x + 3) (5x + 3) - 40 x?] m² = (39x + 9) m?
  • Given: Area of the path = 594 m²: 39x + 9 = 594].
Answered by Anonymous
16

Answer:

Length = 120 meter

Breadth = 75 meter

Step-by-step explanation:

Let the length of the park rectangle ABCD be 8x meter

Let the breadth of the park rectangle ABCD be 5x meter

Area of rectangle ABCD = (8x × 5x) m

=40x² m

Length of the park including path PQRS

=8x + 2 (width of path)

=8x + 2 (1.5)

=8x + 3m

Breadth of the park including path PQRS

=5x + 2 (width of path)

=5x + 2 (1.5)

=5x + 3m

Area of the park including path PQRS

=(8x + 3)(5x + 3)

=(40x² + 39x + 9)m²

Given,

Area of the path=594m²

Area of PQRS - Area of ABCD = 594

=> 40x² + 39x + 9 − 40x = 594

=> 39x = 594 − 9

=> 39x = 585

=> x = 585/39

=> x = 15

Length of the park = 8x

= 8 × 15

= 120m

Breadth of the park=5x

= 5 × 15

= 75m

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