Math, asked by 29Harshadaa, 5 months ago

9. The length of a rectangular garden is 27 feet and its width is 38 ft. What is the new area if
the length is doubled and the breadth is halved?​

Answers

Answered by inamdarmisba112
2

Answer:

1026 ft^2

Step-by-step explanation:

given : length = 27 feet

width = 38 feet

if length doubled, so new length = 54 feet

breadth halved = 38/2 = 19 feet

new area = length * breadth

= 54 * 19

= 1026 ft^2

Answered by adarshtiwariindia
2

Answer:

I think 1026 sq. feet

Step-by-step explanation:

Let the Given length L = 27 feet

and the given width B = 38 feet

according to question

double the length so the new length= 2L

and the half of width be = 1/2B

now put the actual value of Length and width from questions

so,

2x27 = 54

1/2 x 38 = 19

area of rectangle is LxB

so 54x19

1026.

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