Question

9.
The length of a road roller is 2.1m and its diameter is 1.4m. For levelling a ground
500 rotations of the road roller were required. How much area of ground was levelled
by the road roller? Find the cost of levelling at the rate of Rs. 7 per sq. m.​

Answer 1

Answer:

Step-by-step explanation:

L=2.1m,d=1.4m⟹r=0.7m

n=500n=500

Area covered=2n\pi\times r\times l\\=2\times 500\times 0.7\times 2.1\pi=4620m^2=2nπ×r×l

=2×500×0.7×2.1π=4620m

2

Cost of travelling =4620\times 7=Rs.32,340=4620×7=Rs.32,340