Question

9. The lengths of the diagonals of a rhombus are 24 cm and 32 cm, then find its side?​

Answer 1

So,

24cm=12cm(half of 24)

32cm=16cm(half of 32)

Apply Pythagoras theorum,

H²=P²+B²

H²=12cm²+16cm²

H²=144cm+256cm

H²=400cm

H=√400

= 20cm

Therefore,length of the side is 20cm

Hope, this will help you.

Answer 2

Answer:

1.A ll the sides of rhombus are equal.

2.Diagonsls of rhombus bisect each other.

According to the question, AC=24cm and BD=10cm

We need to find the perimeter

AE=EC=12cm and BE=ED=5cm

now in a triangle AED, by Pythagoras theorem

AD^2=AE^2+ED^2

AD^2=12^2+5^2

AD^2=144+25

AD^2=169

AD=13cm

Perimeter=AB+ BC+ CD+ DA=13+13+13+13=52cm