Question

9. The magnitude of the cross product of two
vectors of magnitude 4 units & 5unit is 10 units
Find the angle bet the two vectors​

Answer 1

Answer:

30°

Explanation:

Given

magnitude of Cross product of vectors = 10 units

The maginudes of two vectors are 4 and 5 units respectively

To Find

Angle between two vectors

Solution

Let, the two vectors are A and B

|A| = 4 units

|B| = 5 units

| A×B | = 10 units

Φ = ?

We know that,

$|A \times B | = 2|A| |B| sin \theta$

$1</strong><strong>0</strong><strong> = </strong>2(4)(5)<strong> sin \theta$

$10 = 20 sin \theta$

$sin \theta = \dfrac{10}{20}$

$sin \theta = \dfrac{1}{2}$

$\theta = 30 \degree$