Math, asked by Abhiahek4624, 7 months ago

9. The number 392492 contains two 9s and two 2s.(1) How many times larger is the first 9 compared with the second 9?(11) How many times smaller is the second 2 compared with the first 2?​

Answers

Answered by buddhivantyash
8

Step-by-step explanation:

1) Answer:

There are two 9 in this no. = 392492

i)The amount of first 9

= 9 × 10,000

= 90,000

ii)The amounts of second 9

= 9 × 10

= 90

How many times the first 9 is largre than second 9 ?

= 90,000 ÷ 90

= 1000

1000 times the first nine is larger than second 9

2) Answer:

There are two 2 in this no. = 392492

i) The amount of first 2

= 2 × 1000

= 2000

ii) The amount of second 2

= 2

How many times the first 2 is largre than second 2 ?

= 2000÷2

= 1000

1000 times the first 2 is greater than second 9

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