Question

9.
The parking charge for vehicles in super Delhi Metro is Rs 20 for
first two hrs and Rs. 10 for subsequent hr. Assume total parking
time to be x hrs. (where x>= 2 ) and total parking charge as y.
Write the linear equation for above relation and draw graph. Find the parking charges for 5hrs from graph

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Answer 1

Step-by-step explanation:

Given:

The parking charge for vehicles in super Delhi Metro is Rs 20 for first two hrs and Rs. 10 for subsequent hr. Assume total parking time to be x hrs. (where x>= 2 ) and total parking charge as y.

To find: Write the linear equation for above relation and draw graph. Find the parking charges for 5hrs from graph.

Solution:

Total parking hours : x

For first 2 hours; charge :20 rupees

For next hours:10(x-2) rupees

Total parking charges y= 20+10(x-2)

or

y= 20+10x-20

Solve and simplify this equation.

Linear equation for the situation

y= 10x

Now plot the line from eq1

1) Put x=0

y= 0

(0,0)

2) put x= 1

y= 10

(1,10)

3) put x=2

y= 20

(2,20)

Graph is attatched.X-axis shows parking hours and Y-AXIS shows parking charges in Rs.

Now join these points.

Parking charges for 5 hours are Rs 50.

Hope it helps you.

Answer 2

Step-by-step explanation:

Total parking hours: x

For first 2 hours; charge :20 rupees

For next hours:10(x-2) rupees

Total parking charges y= 20+10(x-2)

or

y= 20+10x-20

Solve and simplify this equation.

Linear equation for the situation

y= 10x

Now plot the line from eq1

1) Put x=0

y= 0

(0,0)

2) put x=1

y= 10

(1,10)

3) put x=2

y= 20

(2,20)

Graph is attatched.X-axis shows parking

hours and Y-AXIS shows parking charges in

Rs.

Now join these points.

Parking charges for 5 hours are Rs 50.

Hence this is your answer