Question

9. The perimeter of a sector of angle 45° of a circle with radius 7 cm is
(a) 19 cm
(b) 19.5 cm
(c) 19/3 cm
(d) 77 cm
​

Answer 1

perimeter of sector = 2*radius + 2πr*terha/360

$= 2 \times 7 + 2 \times \frac{22}{7} \times 7 \times 45 \\ = 14 + 2 \times 22 \times 45 \\ = 14 + 22 \times 90 \\ = 1980 + 14 \\ = 14+1980/360=14+5.5=19.5$

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Answer 2

Hey!

• Radius = 7 cm

• Length of Arc = Theta / 360° × 2πr

• 45°/360° × 2*22/7*7

• 1/8 × 44

• 5.5 cm

• Perimeter of the sector of angle 45° = 2*radius + Length of Arc.

• 2*7 + 5.5 = 19.5 cm

° Option (c) is the right answer °

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