9. The present age of a son is half the present age of his father. Ten years ago, the father
was thrice as old as his son. What are their present age?
10. Two equal sides of a triangle are each 5 metres less than twice the third side. If the
perimeter of the triangle is 55 metres, find the lengths of its sides.
Answers
The present age of son is half the present age of his father.
Let the present age of the father be 2x.
Therefore present age of the son = 2x/2 = x years
According to the question,
10 years ago, father's age was thrice as old as his son.
➡ 3(x - 10) = 2x - 10
➡ 3x - 30 = 2x - 10
➡ 3x - 2x = -10 + 30
➡ x = 20
Hence their present ages are :-
Father's present age = 2x = 40 years
His son's present age = x = 20 years
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Answer:
9)The present age of son is half the present age of his father.
Let the present age of the father be 2x.
Therefore present age of the son = 2x/2 = x years
ATQ,
10 years ago, father's age was thrice as old as his son.
➡ 3(x - 10) = 2x - 10
➡ 3x - 30 = 2x - 10
➡ 3x - 2x = -10 + 30
➡ x = 20
Hence their present ages are :-
Father's present age = 2x = 40 years
His son's present age = x = 20 years
2)
perimeter=55
Let x be the third side of triangle
therefore other two sides=2x-5
Perimeter=x+2x-5+2x-5
55=5x-10
55+10=5x
5x=65
x=65/5
x=13
Therefore the sides of the triangle are 13m, 21m, 21m
Step-by-step explanation:
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