Math, asked by Nandhuchenkal3240, 5 hours ago

9. The present age of a son is half the present age of his father. Ten years ago, the father
was thrice as old as his son. What are their present age?
10. Two equal sides of a triangle are each 5 metres less than twice the third side. If the
perimeter of the triangle is 55 metres, find the lengths of its sides.

Answers

Answered by dayamoyghosh999
0

The present age of son is half the present age of his father.

Let the present age of the father be 2x.

Therefore present age of the son = 2x/2 = x years

According to the question,

10 years ago, father's age was thrice as old as his son.

➡ 3(x - 10) = 2x - 10

➡ 3x - 30 = 2x - 10

➡ 3x - 2x = -10 + 30

➡ x = 20

Hence their present ages are :-

Father's present age = 2x = 40 years

His son's present age = x = 20 years

Please mark it as brainliest

Answered by mrtvmedical173
0

Answer:

9)The present age of son is half the present age of his father.

Let the present age of the father be 2x.

Therefore present age of the son = 2x/2 = x years

ATQ,

10 years ago, father's age was thrice as old as his son.

➡ 3(x - 10) = 2x - 10

➡ 3x - 30 = 2x - 10

➡ 3x - 2x = -10 + 30

➡ x = 20

Hence their present ages are :-

Father's present age = 2x = 40 years

His son's present age = x = 20 years

2)

perimeter=55

Let x be the third side of triangle

therefore other two sides=2x-5

Perimeter=x+2x-5+2x-5

55=5x-10

55+10=5x

5x=65

x=65/5

x=13

Therefore the sides of the triangle are 13m, 21m, 21m

Step-by-step explanation:

Hope it is helpful

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