Question

9. The radius of a wire is decreased to one-
third and its volume remains the same.
The new length is how many times the
original length ?
(A) 1 time (B) 3 times
(C) 6 times (D) 9 times​

Answer 1

πr²h=x → π(r²/9)(yh) = x  πr²h=π(r²/9)(yh)  y = 9 times  (D) 9 times