Math, asked by priya2063, 11 months ago

9. The ratio of Reema's age to Sadhana's age
is 6:7. After 12 years the ratio of their ages
will be 12: 13. Find their present ages.

Answers

Answered by VishnuPriya2801
62

Answer:

12 years, 14 years

Step-by-step explanation:

let , Reema's age and Sadhana's ages be 6x,7x

After 12 years their ages will be 6x+12 and 7x+12

According to the problem,

6x+12+7x+12=12x+13x

13x+24=25x

24=25x-13x

24=12x

X=24/12

X= 2

Therefore, the present ages of Reema and Sadhana are 12 years and 14 years.

Answered by StarrySoul
84

SoLuTiOn :

Let Reema's present age be 6x and Sadhana's age be 7x

After 12 years :

Reema's age = 6x+12

Sadhana's age = 7x+12

According to the Question :

 \rightarrow  \sf \:  \dfrac{6x + 12}{7x + 12}  =  \dfrac{12}{13}

 \rightarrow  \sf \:  13(6x + 12) = 12(7x + 12)

 \rightarrow  \sf \:  78x + 156 = 84x + 144

 \rightarrow  \sf \:  78x - 84x = 144 - 156

 \rightarrow  \sf \:   - 6x =    - 12

 \rightarrow  \sf \:   x =  \dfrac{12}{6}

 \rightarrow  \sf \:   x = 2

Hence,

Reema's age = 6 × 2 = 12 years

Sadhana's age = 7×2 = 14 years

Points to Remember :

* If the present age is m, then t times the present age = tm.

* If the present age is q, then age e years later/hence = q + e.

* If the present age is s, then age b years ago = s – b.

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