Question

9. The ratio of the parallel sides of a trapezium is 2:3. The distance between them is 15 cm. If the area
of the trapezium is 600 cm2, find the lengths of the parallel sides.​

Answer 1

AnSwer -:

The length of parallel sides are 32 cm

and 48 cm.

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Explanation-:

The Area of trapezium-:

“A = 1/2 x h x(a+b)”

A = Area

H = height

(A+b) = sum of parallel sides

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Given,

Area of trapezium-: 600 cm^2

The parallel sides are in ratio 2:3

The distance between them or height of

the trapezium = 15 cm

To find,

Length of parallel sides

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Let the parallel sides of trapezium be

2x and 3x

The Area of trapezium-:

“A = 1/2 x h x(a+b)”

A = Area = 600 cm^2

H = height = 15 cm

(A+b) = sum of parallel sides (2x +3x)

Then ,

1/2 x 15 (2x +3x) = 600

2x + 3x = 600 x 2 / 15

2x + 3x = 80

5 x = 80

X = 80/5

X = 16

Therefore,

The length of parallel sides-:

2x = 2 x 16 = 32 cm

3x = 3 x 16 = 48

Hence ,

The length of parallel sides are 32 cm

and 48 cm.

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Trapezium-: A trapezium is

a type of quadrilateral, which has

only two parallel sides and the other two

sides are non-parallel.

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